【题目链接】:

【题意】

【题解】

把密文;

在表中找到每个字符对应的数字;

然后转换成相应的二进制;

如果不足6位就在二进制的前面补零补到6位;

然后每个字符6个二进制6个二进制地排在一起;

然后8位8位地输出;

->最后可以得到”要你输入一个整数x,然后输出x%2017”;

【Number Of WA】

0

【完整代码】

#include 
     
      using namespace std;#define rep1(i,x,y) for (int i = x;i <= y;i++)#define LL long longmap 
      
        dic;string s,temp;int a[20],tot,x;string cl(int x){    string d = "";    while (x)    {        d=char((x&1)+'0')+d;        x>>=1;    }    while (int(d.size())<6) d='0'+d;    return d;}char out(){    int d = 0;    for (int now = 1,i = 8;i>=1;i--)    {        d+=a[i]*now;        now<<=1;    }    char t = d;    return t;}int main(){    //freopen("D:\\rush.txt","r",stdin);    for (char key = 'A';key<='Z';key++)        dic[key]=key-'A';    for (char key = 'a';key<='z';key++)        dic[key]=key-'a'+26;    for (char key = '0';key<='9';key++)        dic[key]=key-'0'+52;    dic['+']=62,dic['/']=63;    //cin >> s;    s="d2hhdCBpcyB0aGUgcmVtYWluZGVyIHdoZW4gdGhlIG51bWJlciBpcyBkaXZpZGVkIGJ5IDIwMTc/";    temp="";    int len = s.size();    rep1(i,0,len-1)    {        temp+=cl(dic[s[i]]);    }    len = temp.size();    //cout << temp<
       
        “what is the reminder of x after divided by 2017"    */    int T;    cin >> T;    while (T--)    {        cin >> x;        cout << x%2017<